Talk:Minishark

"Ammo consumption: The Minishark's special ability makes it so that it will averagely shoot about 333 (250*133%)" Erm, isn't it supposed to be a 33% chance of not using ammo? Because that would be 375 rounds (250*150%), not 333 rounds. Woden 01:14, 15 August 2011 (UTC) (I suck at Wiki formatting. :
 * Yes, it's a 33% chance of not using ammo. No, it's not 375 rounds. I'm not sure where you even got that number from. --Lunboks 01:24, 15 August 2011 (UTC)
 * 150% would be the equation if there were a 50% chance of not consuming ammo.
 * In other words: One third of the 250-count stack will not be consumed on average, which equals 83 shots rounded. 250 (actual stack) + 83 average gain = 333.
 * Your way, 375 shots from a 250-count stack would be a 125 shot gain, which is half the actual stack of 250, a 50% gain.  Equazcion ( talk ) 01:27, 15 Aug 2011 (UTC)
 * Your way, 375 shots from a 250-count stack would be a 125 shot gain, which is half the actual stack of 250, a 50% gain.  Equazcion ( talk ) 01:27, 15 Aug 2011 (UTC)

ok there is a huge confusion due to math. i can see an additive percentage gain or (two) multiplicative percentages. 1/3 + 1/5 = 5/15 + 3/15 = 8/15 = .53 (repeating 3's) = 153% (computers love dropping final numbers' digits). 1.33 * 1.2 = 1.596 = 160% (rounded up) OR  4/3 * 1.2 [basically 1/5 already done] = 1.6 = 160%. any questions? i personally think it is the later equation due to my experiences with games' percentages with math. 96.13.59.60 03:50, 15 August 2011 (UTC)
 * The source code uses fractions rather than percents. The statement for deciding a random occurrence looks something like "if rand(10) = true then...", meaning "pick a random number from 1 to 10, and if that number equals 1, do ..." Stacked randoms (though I haven't looked at those yet) probably look like "if rand(10) or rand(3) then..." My math skills aren't awesome so I wouldn't know exactly how to calculate a percent that totals the two chances.  Equazcion ( talk ) 03:58, 15 Aug 2011 (UTC)